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Classification of ligands on the basis of bonding
Ligands are of two types ---
- Loan pair donar
They form sigma or single coordinate bond by donating loan pair to central metal atom. (as you read previous)
- Pie- electron donar
Those compound which contain pie-bond, may donate their pie electrons. They form no bond by donating their pie electron unless they regain their electron in their antibonding orbitals. While regain their pie electron, they form back bond named as Sinergic Bond with central metal atom.
Example :-
CH2CH2 (monodentate) |
||
C6H6 (tridentate) represented by n-C6H6. |
[Cr(C6H6)2] (dibenzene Chromium) |
Sometimes electron may be transferred from filled orbitals of central atom to vacant orbitals of the ligands and this type of back bonding is known as Sinergic bonding.
On the basis of Sinergic bonding, ligands are of two types :--
- Classical ligands
They only donate pie bond to central atom and there is no back bonding.
Example :- F-, OH-, H2O, NH3 etc.
- Non-Classical ligands (pie-acid ligand)
They donate pie electron but they form pie-bond with central atom by taking electron from filled orbital of central atom as Sinergic bonding.
Example :-CO vacant pie*
(pie-antibonding orbital)PH3 vacant d-orbital CN- PF3 NC- PR3 NO+ PPH3 C2H4 H2S C6H6 CH3X
(X-halogens)C5H5 Question - When CO form coordination complex, bond length of CO increases. Explain.
===> If Z-effect of central atom decreases, Sinergic bonding increases.
Answer -During Sinergic bonding, CO accept electron in pie* (pie-antibonding orbital) due to which bond order decreases, hence bond length increases.
Sidwick's EAN rule
EAN = Effective atomic number.
EAN = atomic number of central atom - Primary valancy (charge on central atom) + 2 * secondary valancy. Sc Ti V Cr Mn Fe Co Ni Cu Zn -------------------- 36Kr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd -------------------- 54Xe La Hf Ta W Re Os Ir Pt Au Hg -------------------- 86Rn
Example :-
K4[Fe(CN)6]
EAN = atomic number of Fe - charge on Fe + 2 * secondary valency of Fe
EAN = 26 - 2 + 2 * 6 = 36. (follow EAN rule)[Co(gly)3] 27 - 3 + 2 * 6 = 36 [Ag(NH3)2]+ 47 - 1 + 2 * 2 = 50 [Fe(en)2ClBr]I 26 - 3 + 2 * 4 + 2 + 2 = 35
[Cr(CO)x]
EAN = 36
36 = 24 - 0 - 2 * x
x = 6.
[Cr(CO)6][Fe(CO)x]
EAN = 36
36 = 26 - 0 + 2 * x
x = 5.
[Fe(CO)5][Ni(CO)x]
EAN = 36
36 = 28 - 0 + 2 * x
x = 4.
[Ni(CO)4]Hx[Co(CO)4]
EAN = 36
36 = 27 -(-x) + 2 * 4
x = 1.
H[Co(CO)4]
A] By Redox Reaction :-
- [Mn(CO)5] ------- + e- -------> [Mn(CO)5]- (act as oxidising agent)
EAN for [Mn(CO)5] is = 35 and that of [Mn(CO)5]- is = 36.
Here reduction take place for Mn.
- 2[Mn(CO)5] --------------------------------> [Mn2(CO)10]
EAN for [Mn(CO)5] is = 35 and that of [Mn2(CO)10] is = 36.Organo Metallic compound
M <------ C { C from alkyl, aryl or CO }.
Example :-Compound Organo Metallic [Cr(C6H6)2] Yes [Fe(C5H5)2] Yes [Ni(CO)4] Yes [PtCl3(C2H4)2]
Zesse's saltYes K4[Fe(CN)6] No [CH3MgCl] Yes [CH3ZnCl] Yes Werner's Coordination theory :-
- In complex compound central atom shows two type of valancy :- 1] Primary valancy. 2] Secondary valancy.
- Primary valancy is satisfied by negative ion and secondary valancy is satisfied by negative, positive or neutral ion.
- Primary valancy is ionisable and non-directional whereas secondary valancy is non-ionisable and directional.
Example :-
CrCl3.6H2O. = Primary valancy (PV) = +3, Secondary valancy = 6.A) [Cr(H2O)6]+3Cl3
after ionisation, 4 ion will formB) [Cr(H2O)5Cl]+2Cl2.H2O
after ionisation, 3 ion will formC) [Cr(H2O)4Cl2]+Cl.2H2O
after ionisation, 2 ion will formdotted line indicates that here Cl only satisfied primary valancy and solid line satisfied secondary valancy. here one Cl is joined by solid and dotted line which indicate that one Cl satisfied primary and secondary valancy both while other two satisfied only secondary valancy. One H2O molecule lie outside the coordination sphere. here two Cl is joined by solid and dotted line which indicate that two Cl satisfied primary and secondary valancy both while other one satisfied only secondary valancy. Two H2O molecule lie outside the coordination sphere. Electrical conductance depend on no. of ion formed. If produced ions are same in number, then compound which contain higher charge, will have more Electrical Conductance.
Electrical conductance ----- (A) > (B) > (C)We do not have to find exact value of electrical conductance. We have to just compare the electrical conductance. We have to compare how many ions will form after ionisation. You may think that why not all Cl come inside coordination sphere and put 3H2O outside the sphere. But you have to always remember that water molecule are neutral and it will not lie outside without any ion. As you see above in fig. 2 & 3, atleast one Cl atom lie outside the sphere so H2O lie outside. If all Cl lie inside sphere then there will no charge on sphere. Hence no attraction between sphere and H2O molecule. IUPAC name of Coordination Compound :-
Name of complex if formula is given :-
- Name of positive part written is followed by name of ligands.
- For simple ion, we write its simple name.
- In complex ion, name of ligands is written first followed by name of central atom.
- There should be a single letter gap between name of cation and anion.
- First letter of name should be capital.
Example :- K4[Fe(CN)6] = Potassium hexacynoferrate.Rules for naming of Central atom :-
- If coordination sphere is neutral or positively charged, then central atom is given its simple name followed by primary valancy in Roman numerals.
Example :- [Cu(NH3)4]SO4 = tetraaminecopper(ii)sulphate.- If coordination sphere is negatively charged, then the term 'ate' in the name of central atom is added.
Example :- K4[Fe(CN)6] = Potassium hexacynoferrate.Atom Name Atom Name Lead (Pb) Plumbate Vanadium (V) Vanadate Tin (Sn) Stanate Chromium (Cr) Chromate Boron (B) Borate Molybdenum (Mo) Molybdate Aliminium (Al) Aluminate Manganese (Mn) Manganate Scandium (Sc) Scandanate Iron (Fe) Ferrate Titanium (Ti) Titanate Osmium (Os) Osmate Cobalt (Co) Cobaltate Rhodium (Rh) Rhodate Iridium (Ir) Irridate Nickel (Ni) Nickilate Palladium (Pd) Palladate Platinum (Pt) Platinate Copper (Cu) Cuprate Gold (Au) Aurate Zinc (Zn) Zincate Cadmium (Cd) Caddimate Mercury (Hg) Mercurate Ruthenium (Rh) Rhodate Rules for naming of Ligands :-
- Different ligands are arranged in alphabetical order.
- Number of ligands is written in Greek numerals.
Example :-
2 - bi
3 - tri
4 - tetra etc.
- If the name of ligand itself contain Greek numerals then for -
2 - bis
3 - tris
4 - tetracis
5 - pentacis etc.
- Name of ligands depends on charge present
- Neutral ligands :-
Simple name will written.
Example :-
CO - carbonyl PH3 - Phosphine PPH3 - triphenylphosphine PMe3 - trimethylphosphine C2H4 - ethylene C6H6 - benzene en - ethylenediamine * H2O - aqua * NH3 - ammine Me-O-Me - dimethylether Me-S-Me - dimethylthioether - Positive ligands :-
the term 'ium' is added.
Example :-
NO+ = nitrosonium or nitrosylium
N2H5+ = hydrazenium - Negative ligands :-
Till 2004, at the place of 'ide', 'o' is added but after 2004, at the place of 'ide', 'ido' is added.
Liketill 2004 after 2004 ide o ido ite ito ito ate ato ato Till 2004 After 2004 Cl- Chloro Chlorido O2- oxo oxido O22- peroxo peroxido O2- superoxo superoxido O3- ozonido ozonido S2- sulphido sulphido N3- azido azido N3- nitrido nitrido OH- hydroxo hydrido NO2- nitrito ClO2- chlorato SO32- sulphito SO42- sulphato CO32- carbonato C2O42- oxalato CH3COO- acetato gly- glycenato dmg- dimethylglyoximato acac- acetylacetonato edta4- ethylenediaminetetraacetato S2O32- thiosulphato Read more
- Neutral ligands :-
- Name of positive part written is followed by name of ligands.
- In complex compound central atom shows two type of valancy :- 1] Primary valancy. 2] Secondary valancy.
- [Mn(CO)5] ------- + e- -------> [Mn(CO)5]- (act as oxidising agent)
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